Interval List Intersections
PROBLEM
You are given two lists of closed intervals, firstList
and secondList
, where firstList[i] = [starti, endi]
and secondList[j] = [startj, endj]
. Each list of intervals is pairwise disjoint and in sorted order.
Return the intersection of these two interval lists.
A closed interval [a, b]
(with a<=b
) denotes the set of real numbers x
with a<=x<=b
.
The intersection of two closed intervals is a set of real numbers that are either empty or represented as a closed interval. For example, the intersection of [1, 3]
and [2, 4]
is [2, 3]
.
Example 1

*Input*: firstList = [[0,2],[5,10],[13,23],[24,25]], secondList = [[1,5],[8,12],[15,24],[25,26]]
*Output*: [[1,2],[5,5],[8,10],[15,23],[24,24],[25,25]]
Example 2
*Input*: firstList = [[1,3],[5,9]], secondList = []
*Output*: []
SOLVING
We’ll use Two Pointers method to solve this problem.
Steps
- Create the variable
result
- Place
LeftPtr
to first list infirstList
andRightPtr
to first list insecondList
- While
LeftPtr
andRightPtr
aren’t superior offirstList
andrightList
size:Start
value of theintersectedList
equalmax
between first element ofLeftPtr
andRightPtr
End
value of theintersectedList
equalmin
between last element ofLeftPtr
andRightPtr
- If
Start
is inferior or equal toEnd
you can push yourintersectedList
toresult
- if
End
equal toLeftPtr
last element, increaseLeftPtr
otherwiseRightPtr
- Return
result
Code
class Solution {
public:
vector<vector<int>> intervalIntersection(vector<vector<int>> &firstList,
vector<vector<int>> &secondList) {
vector<vector<int>> result;
int leftPtr = 0;
int rightPtr = 0;
while (leftPtr < firstList.size() && rightPtr < secondList.size()) {
vector<int> intersectedList;
int start = max(firstList[leftPtr][0], secondList[rightPtr][0]);
int end = min(firstList[leftPtr][1], secondList[rightPtr][1]);
if (start <= end) result.push_back({start, end});
(end == firstList[leftPtr][1]) ? leftPtr++ : rightPtr++;
}
return result;
}
};